![]() Noah Brautigam, the 2020 Speedgoat 50k winner, finished in 2:26. Now a few notes from sometimes trail runners and ultrarunners at the weekend’s Berlin Marathon. Robert Loic (France) and Mathilde Sagnes (France) won in 1:52 and 2:20, both two minutes up on their closest chasers. It was slightly less competitive than in 2021 then, but still attracted a number of Europe’s best. This 21k race was part of last year’s Golden Trail World Series. Tefera Mekonen (Ethiopia) and Iseli Rea (Switzerland) won the 15k race in 1:10 and 1:21. homegrown Cirque Series went international for the first time. Christin Mathys (Switzerland) and Oihana Azkorbebeitia (Spain) topped everyone in 4:49 and 5:50, respectively. The Skyrunner World Series stopped in Bulgaria for Pirin Extreme, a 38k run with 3,300 meters of gain. The 59k winners were Tao Luo (China) and Marie Perrier (Mauritius) in 5:54 and 6:42, and that’s got to be our first Mauritius mention here in This Week in Running. He finished a dominant first in 1:53, four minutes better than everyone else. Known for his uphill prowess, there was a chance he’d get run down on this up-and-down course, but nah, Bonnet extended his lead in the race’s second half. Ten minutes into the race, Rémi Bonnet(Switzerland) was already 20 seconds up on a big chase pack. And for the avoidance of doubt, 26 kilometers match just over 16 miles. The ski area course went up right from the start, all the way to 11,500 feet above sea level, and then back down. Dozens of runners explored Moab, Utah, and Monument Valley, Arizona, together on their road trip to Flagstaff. For most of the international runners, it looks like they had a great week in between the two races. Flagstaff Sky Peaks 26k – Flagstaff, ArizonaĪfter last weekend’s Pikes Peak Ascent, this one was the second Golden Trail World Series race in as many weeks. The Flagstaff Sky Peaks race, USATF Trail Half Marathon National Championships, and M ammoth Trail Fest all passed too, and so Monday morning, we’re doing what we do, talking ’bout it. That’s what Green Day tells me, and I used to love that song. The resulting solved free body diagram is shown in Part (b) of Figure 4.11.There are a few days left in September, but I guess summer has come and passed. The total vertical load here will be equal to $w_ For the case of a snow load, only a certain amount of snow can fall from a certain area of sky, so the greater the inclination of the member, the longer the length that the snow will be spread out over (making the load per unit of member length lower). The fourth and final type (`snow-type') is a distributed load which is not perpendicular to the member and is also not distributed along the member length, but along the horizontal projection of the member (in this case, the distance $L$). In this case, a direct trigonometric transformation may be used to split the vertical distributed load into two different components, one perpendicular to the member (which will cause shear and bending) and one parallel to the member (which will cause axial load) as shown in the figure. This type of load is also distributed along the diagonal length of the member since the source of the load (in this case, the dead weight of the member) is also distributed along the diagonal length. In this case, it is aligned with the global vertical axis direction to simulate the effect of a vertical gravity (or 'dead') load. The third type ('dead-type') is a distributed load that is not applied perpendicular to the member. Since the load is already perpendicular to the member, no transformation is needed. ![]() The distributed load is applied directly perpendicular to the inclined member and is distributed along the diagonal length of the member ($L/cos\theta$ in this case). The second type (`wind-type') is typical of distributed loadings caused by wind or other pressure-type loadings. The first type shows the transformation of point loads on an inclined member into parallel and perpendicular components. Four different types of inclined loadings are shown in the figure. Sample geometry for an inclined member is shown at the top of Figure 4.7. Figure 4.7: Resolving Loads on Inclined Members into Local Axis Directions
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